Now we need to interpolate on c to get 20+(35-20).2 = 23. If there is not table value for alpha =.03, but there are table values for alpha =.02 and.05, then you repeat the above process to get a value where r = 4.5, c = 3.2 and alpha =.02. You also repeat this process to get a value for r = 4.5, c = 3.2 and alpha =.05. Excel Linear Interpolation Linear interpolation in excel means forecasting or guessing the upcoming next value of any certain variable given on the current data, here we create a straight line which connects two values and we estimate the future value through it, in excel we use forecast function and a lookup function to do a linear interpolation.
- Excel Interpolate Table Function
- Excel Interpolate Table Definition
- Excel Interpolation Equation
- Excel Linear Interpolation From Table
- Excel Linear Interpolate Table
I've recorded engine data and two of the variables recorded were engine speed and coolant temperature. To determine friction torque, the table below needs to be used:
Engine Speed | 400 | 800 | 1000 | 1100 | 1200 | 1300 | 1400 | 1500 | 1600 | 1800 | 2000 | 2200 | 2400 | 2600 | 2800 | 3000 |
Coolant Temperature | ||||||||||||||||
-30.04 | 80 | 96 | 104.4 | 108.9 | 113 | 117.8 | 122.7 | 127.6 | 132.5 | 141 | 148 | 156 | 161.7 | 168 | 176 | 183 |
-20.04 | 65 | 82 | 90.2 | 93.9 | 98.1 | 102.6 | 107.5 | 112 | 117.3 | 125 | 132.3 | 139.2 | 144.9 | 150 | 156.2 | 162 |
-10.04 | 55 | 69 | 76 | 80.3 | 83.6 | 87.8 | 92 | 96.5 | 101 | 107.7 | 115 | 121 | 127.5 | 133.7 | 139.3 | 145 |
-0.04 | 48 | 59 | 63 | 66.8 | 69.5 | 72.9 | 76.8 | 80.6 | 85 | 92.5 | 99 | 106 | 113 | 119.1 | 125.7 | 133 |
9.96 | 45.5 | 54.3 | 58.7 | 60.8 | 62.7 | 66 | 69 | 72.9 | 77 | 85 | 92 | 100 | 106 | 112.5 | 119 | 125.5 |
19.96 | 43.8 | 52.3 | 56.5 | 58.5 | 60.4 | 63.6 | 65.9 | 69.1 | 72.2 | 80.1 | 87.1 | 95 | 102.1 | 108 | 115 | 120.9 |
29.96 | 42.2 | 50.3 | 54.4 | 56.3 | 58.1 | 61.2 | 63.5 | 66.5 | 69.5 | 77.1 | 83.9 | 91.5 | 98.3 | 104 | 110.5 | 116.4 |
39.96 | 40.5 | 48.4 | 52.3 | 54.1 | 55.9 | 58.8 | 61 | 63.9 | 66.7 | 74 | 80.6 | 87.9 | 94.4 | 100 | 106 | 111.8 |
49.96 | 39.3 | 43.8 | 46.6 | 48 | 49.3 | 51.5 | 53.2 | 55.5 | 57.6 | 63.1 | 68.2 | 73.9 | 80.5 | 86 | 92 | 100.3 |
59.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
69.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
79.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
89.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
99.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
109.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
119.96 | 38 | 39.2 | 40.8 | 41.8 | 42.7 | 44.1 | 45.4 | 47 | 48.5 | 52.1 | 55.8 | 59.8 | 66.5 | 73.2 | 80.9 | 88.7 |
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The values in the main body of the table are friction torque. I would like to be able to calculate friction torque for a range of engine speeds and coolant temperatures. I think I have to interpolate the table to do this. How do I interpolate the table on Excel?
Below is a small sample of my spreadsheet. I would like a formula to calculate the friction torque by using the values in the engine speed and coolant temperature columns, and then using the table above. Any suggestions?
Coolant Temperature (°C) | Engine Speed (rpm) | Friction Torque (Nm) |
30 | 940 | |
30 | 940 | |
30.16 | 940 | |
30.16 | 937 | |
30.2 | 937.5 | |
30.5 | 938 | |
30.6 | 941 | |
30.6 | 941 | |
31 | 941 | |
31 | 940.5 | |
31 | 939 | |
31 | 938.5 | |
31 | 939.5 | |
31.9 | 940 | |
32 | 941.5 | |
32.5 | 942.5 | |
32.5 | 939 | |
32.5 | 939.5 | |
32.6 | 941.5 | |
33 | 942 | |
33.4 | 942.5 | |
33.5 | 943 | |
35 | 942 |
Excel Interpolate Table Function
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